Final answer:
A sample of CH4O with a mass of 32.0 g contains 6.012 x 10^23 molecules of CH4O.
Step-by-step explanation:
The number of molecules in a sample of CH4O can be calculated by dividing the mass of the sample by the molar mass of CH4O and then multiplying by Avogadro's number, which is 6.022 x 1023 molecules/mol. Given that the mass of the sample is 32.0 g, we can calculate:
Number of molecules = (mass of sample / molar mass) x Avogadro's number
= (32.0 g / molar mass of CH4O) x 6.022 x 1023 molecules/mol
To determine the molar mass of CH4O, we need to calculate the sum of the atomic masses of carbon (C), hydrogen (H), and oxygen (O) in one molecule of CH4O.
Atomic mass of C = 12.01 g/mol
Atomic mass of H = 1.008 g/mol
Atomic mass of O = 16.00 g/mol
Therefore, molar mass of CH4O = (12.01 g/mol) + (4 x 1.008 g/mol) + 16.00 g/mol = 32.04 g/mol
Now, substituting this value in the formula:
Number of molecules = (32.0 g / 32.04 g/mol) x 6.022 x 1023 molecules/mol
= 6.012 x 1023 molecules