Question

Please?
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Answer 1

`a^(2)` is just a*a, and
`a^(4)` is a*a*a*a

Thus, adding them together is a*a a*a*a*a, or
`a^(6)`

Alternatively, use the rule

`a^(m) +a^(n) =a^(m+n)`

When used in this problem:

`a^(2) +a^(4) =a^(2+4) = a^(6)`

I hope this helps!