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A force of 50.0 N directed to the right acts on an object with a mass of 10.0 kg. Friction is 30.0 N. What is the magnitude of the resultant acceleration of the object

A force of 50.0 N directed to the right acts on an object with a mass of 10.0 kg. Friction-example-1
User Daniel Naber
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1 Answer

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Force = F = 50 N (right)

mass = m = 10 kg

Friction force = Fr = 30N

a = acceleration

Apply Newton's Second Law:

∑F = m a

F - FR = m * a

replacing:

50 - 30 = 10 * a

20 = 10 *a

20/10 = a

a = 2 m/s^2

A force of 50.0 N directed to the right acts on an object with a mass of 10.0 kg. Friction-example-1
User Mikus
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2.7k points