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If two hundred grams of O2 at 1 atm occupies a volume of 300 L, calculate the temperature of the gas.

User Orionpax
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1 Answer

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24 votes

Answer: T = 311.94 degrees Celsius

Step-by-step explanation:

We would apply the ideal gas equation which is expressed as

PV = nRT

where

P is the pressure of the gas in atm

V is volume of the gas in liters

n is the number of moles

R is the gas constant and its value is 0.08206L.atm/K.mol

L is the volume in liters

We would calculate the number of moles, n by applying the formula,

n = mass/molar mass

From the information given,

mass = 200 g

molar mass of oxygen = 32

number of moles, n = 200/32 = 6.25

V = 300

P = 1

By substituting these values into the formula,

1 x 300 = 6.25 x 0.08206 x T

300 = 0.512875T

T = 300/0.512875

T = 584.94 K

We would convert to Celsius by subtracting 273. Thus,

T = 584.94 - 273

T = 311.94 degrees Celsius

User Dim
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