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The product of 2 consecutive natural numbers is greater than their sum by 109. find the numbers
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The product of 2 consecutive natural numbers is greater than their sum by 109. find the numbers

User Ahmad Bawaneh
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1 Answer

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Let the 2 consecutive numbers be n and n+1. Then:
n(n+1)-109=n+n+1
n²+n-109-2n-1=0
n²-n-110=0
(n-11)(n+10)=0
n=11
n+1=12
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User Mahmoud Alkomy
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8.9k points
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