We need 10 liters of 90% bleach.
We have pure bleach (p) and 20% bleach (m)
A) p + m = 10 liters
B) p + .2m = (.90 * 10)
multiplying equation B by -1
B) -p - .2m = -9 then adding equation A
A) p + m = 10
.8 m =1
m = 1.25 liters of 20% bleach
p = 8.75 liters of 100% bleach
Double Check
The 1.25 liters of 20% bleach contains .25 liters of pure bleach.
Basically, we have (8.75 liters + .25 liters) 9 liters of pure bleach in a volume of 10 liters. 9 / 10 = .9 equals 90%