Question

Which of the following describes the domain of y = tan x, where n is any integer? A.x≠2nπ B. x≠π/2+nπ C. x≠nπ D.x≠nπ/2

Answer 1

`\bf tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}`

therefore, that fraction will become undefined if the denominator ever turns to 0.

now, recall that cos(π/2) is 0, and cos(3π/2) is 0, and cos(5π/2) is also zero and so on, thus


`\bf tan\left( (\pi )/(2) \right)=\cfrac{sin\left( (\pi )/(2) \right)}{cos\left( (\pi )/(2) \right)}\implies tan\left( (\pi )/(2) \right)=\cfrac{sin\left( (\pi )/(2) \right)}{0} \\\\\\ tan\left( (3\pi )/(2) \right)=\cfrac{sin\left( (3\pi )/(2) \right)}{cos\left( (3\pi )/(2) \right)}\implies tan\left( (3\pi )/(2) \right)=\cfrac{sin\left( (3\pi )/(2) \right)}{0}`


`\bf tan\left( (5\pi )/(2) \right)=\cfrac{sin\left( (5\pi )/(2) \right)}{cos\left( (5\pi )/(2) \right)}\implies tan\left( (5\pi )/(2) \right)=\cfrac{sin\left( (5\pi )/(2) \right)}{0} \\\\\\ tan\left( (7\pi )/(2) \right)=\cfrac{sin\left( (7\pi )/(2) \right)}{cos\left( (7\pi )/(2) \right)}\implies tan\left( (7\pi )/(2) \right)=\cfrac{sin\left( (7\pi )/(2) \right)}{0}`


`\bf tan\left( (\pi )/(2)+\pi \right)=\cfrac{sin\left( (\pi )/(2)+\pi \right)}{cos\left( (\pi )/(2)+\pi \right)}\implies tan\left( (\pi )/(2)+\pi \right)=\cfrac{sin\left( (\pi )/(2)+\pi \right)}{0} \\\\\\ domain\implies \{x|x\in \mathbb{R}, ~~x\\e (\pi )/(2)+n\pi,~~n\in \mathbb{Z} \}`