Question

How do you solve 2x²-x=3 by factoring

Answer 1

the answer for your question is 2x^2-x-3=0
so, by factoring it we have. (2x-3)*(x+1)

Answer 2

the value of x are -1 and
`(3)/(2)`

Explanation:

we need to find the factor of 2x²-x=3

subtract both the sides by 3, in above expression

2x²- x - 3 = 3 - 3

2x²- x - 3 = 0

we can write x as -3x + 2x

2x²- 3x +2x - 3 = 0

2x²+ 2x -3x - 3 = 0

take out the common terms,

2x(x+ 1) -3(x +1) = 0

(x+ 1)(2x-3) = 0

If x+ 1 =0

⇒ x = -1

If 2x - 3=0

⇒
`x=(3)/(2)`

Therefore, the value of x are -1 and
`(3)/(2)`