Question

4^2-6(2^x)-16=0


solve for x

Answer 1

Assuming that 4^2-6(2^x)-16=0 is correct, we can rearrange it as:

-6(2^x) + 4^2 - 16=0

Are you sure it's not 6(2^x) + 4^2 - 16=0 ?

If 6(2^x) + 4^2 - 16=0 is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)