Question

Divide: (2n3+4n−9)÷(n+2).

Answer 1

The question gives the dividend as

`2n^3+4n-9`

and the divisor as

`n+2`

STEP 1: Divide the leading term of the dividend by the leading term of the divisor. Write down the calculated result in the upper part of the table and multiply it by the divisor:

STEP 2: Divide the leading term of the obtained remainder by the leading term of the divisor. Write down the calculated result in the upper part of the table and multiply it by the divisor:

STEP 3: Divide the leading term of the obtained remainder by the leading term of the divisor. Write down the calculated result in the upper part of the table and multiply it by the divisor:

Therefore, the answer is

`2n^2-4n+12-\frac{33}{n+2_{}}`