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Determine the margin of error for the confidence interval for the proportion:0.567 < p <0.818The margin of error is

Determine the margin of error for the confidence interval for the proportion:0.567 &lt-example-1
User Waldheinz
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1 Answer

12 votes
12 votes

Answer: 0.1255

Given the confidence interval proportion:


0.567<p>We are going to solve for the margin of error. To do that, we must first solve for the sample proportion of the given confidence interval. We just need to get the average of the lower and upper bound confidence interval</p>[tex]\hat{p}=\frac{0.567+0.818_{}}{2}=0.6925

Now that we got the sample proportion, we can now solve for the margin of error based on the formula below:


CI=(\hat{p}-E,\hat{p}+E)

Now, since CI = ( 0.567, 0.818 ), we can solve this as:


\hat{p}-E=0.567
E=0.6925-0.567=0.1255
\hat{p}+E=0.818
E=0.818-0.6925=0.1255

Therefore, the margin of error is 0.1255

User Luisfer
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