Question

Which equation could be solved using this application of the quadratic formula? x=-2 + 2/2 -2(1) 4(1) (-4)

Answer 1

`x^(2)+2x-1=3`

Explanation:

The quadratic formula is given as;

`\begin{gathered} x=(-b\pm√(b^2-4ac))/(2a) \\ where, \\ ax^2+bx+c=0\text{ is the quadratic function form} \end{gathered}`

Therefore, for the given quadratic formula, identify the values for a,b, and c.

a=1, b=2, and c=-4.

Hence, the equation that could be solved using the application above:

`\begin{gathered} x^2+2x-1=3 \\ x^2+2x-4=0 \end{gathered}`