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Write the standard form of the line that passes through the point (-2, 4) and is parallel to x - 2y = 6. Type your answer in the box provided or use the upload option to submit your solution.

User Cetin Sert
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2 Answers

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Answer:
x-2y=-10

Explanation:

Write
x - 2y = 6 in intercept form(
y=mx+c).


2y =x- 6


y =dfrac{x- 6}{2}


y =dfrac{x}{2}-3

Here , slope of line
x - 2y = 6 =
m=(1)/(2) (Coefficient of x)

Also , the slope of two parallel lines are equal.

Equation of line passing through point (a,b) and has slope m is given by :_


(y-b)=m(x-a)

Standard form of equation :
Ax+By= C ,where A is positive integer a,d B and C be any integer.

Equation of the line parallel to line
x - 2y = 6 and passing through (-2, 4) will be :-


(y-4)=(1)/(2)(x-(-2))\\\\ 2(y-4)=(x+2)\\\\ 2y-2(4)=x+2\\\\2y-8=x+2\\\\ x-2y=-8-2\\\\ x-2y=-10\ \ {\text{(Standard form)}}

User Feona
by
8.3k points
2 votes
Rewrite the equation: 2y=x-6, y=x/2-3, so slope is 1/2 which is also the slope of the parallel line.
It will have the equation y=x/2+a where a is found by plugging in the given point: 4=-1+a, so a=5.
Therefore y=x/2+5. (This can also be written 2y=x+10 or x-2y+10=0)
User Jake Rote
by
8.2k points

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