Question

What are the coordinates of the orthocenter of △ABC with vertices at A(1, 2) , B(1, 6) , and C(5, 6) ?

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Answer 1

......ok.....the orthocenter would be at (1,6)

Answer 2

Solution: A triangle ABC having vertices at A(1, 2) , B(1, 6) , and C(5, 6).

AB= 4 units

BC= 4 units

CA =
`\sqrt{(5-1)^(2) +(6-2)^(2) }=√(32)=4√(2)`

The triangle ABC is right angled triangle.

And Orthocentre of a triangle is the point where perpendiculars of triangle meet.As two perpendiculars AB and AC meet at Point B , So Point B(1,6) is orthocenter of triangle.