Question

What is the total perimeter of the pitch and seating area?

What is the total area of the pitch and seating area?

Answer 1

1m = 100 cm

so
40 m = 4,000 cm
25 m = 2,500 cm
10 m = 1,000 cm

perimeter of big rectangle = 2(4,000 + 2000) = 12,000 cm
perimeter of small rectangle on the left: 2(2,500 + 800) = 6,600 cm
perimeter of small rectangle on the right: 2(1,000 + 800) = 3,600 cm
perimeter of circle = πd = 3.141593 x 200 = 628.32 cm

total area of the pitch and seating area :
= 12,000 + 6,600 + 3,600 + 628.32 = 22,828.32 cm

answer
22,828.32 cm

Answer 2

The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²

Explanation:

Figure is attached with required naming.

Length of the Rectangle 1 = 40 m

width of the Rectangle 2 = 2000 cm = 20 m

radius of semi circle 2 =
`(2000)/(2)=1000=10\,m`

radius of semi circle 3 =
`(2000)/(2)=1000=10\,m`

length of the rectangle 4 = 25 m

width of the rectangle 4 = 800 cm = 8 m

length of the rectangle 5 = 10 m

width of the rectangle 5 = 800 cm = 8 m

Total Perimeter of the pitch and seating area

= length of rectangle 1 + circumference of semi circle 2 + circumference of semi circle 3 + length of rectangle 4 + 2 × width of rectangle 4 + length of rectangle 5 + 2 × width of the rectangle 5 + (length of rectangle 1 - length of rectangle 4 - length of he rectangle 5)

= 40 + π(10) + π(10) + 25 + 2 × 8 + 10 + 2 × 8 + ( 45 - 25 -10 )

= 40 + π(10) + π(10) + 25 + 16 + 10 + 16 + 10

= 117 + 20π

= 179.83 m (approx.)

Total area of the pitch and seating area

= Area of the Rectangle 1 + Area of semi circle 2 + area of semi circle 3 + area of rectangle 4 + area of rectangle 5

= 40 × 20 + π(10)² + 25 × 8 + 10 × 8

= 800 + 100π + 200 + 80

= 1080 + 314

= 1394 m²

Therefore, The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²