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14 votes
14 votes
A number from 15 to 23 is drawn at random p(a number divisable by 3)

User Tyrannas
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1 Answer

20 votes
20 votes

Solution:

Given:


\begin{gathered} Sample\text{ space}=\lbrace15,16,17,18,19,20,21,22,23\rbrace \\ Total\text{ n}umber\text{ of possible outcomes}=9 \\ \\ \\ Numbers\text{ divisible by 3}=\lbrace15,18,21\rbrace \\ Number\text{ of required outcome}=3 \end{gathered}

Therefore, the probability of picking a number divisible by 3 is;


\begin{gathered} P(a\text{ number divisible by 3\rparen}=(3)/(9) \\ \\ Simplifying\text{ further,} \\ P(a\text{ number divisible by 3\rparen}=(1)/(3) \end{gathered}

User Yashu Seth
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