Question

What is the impulse that a car with a mass of 6kg experiences when its velocity changes from 23m/s to 6m/s?

What is the impulse that the wall creates when it applies a force of 29N over a period of 7s in a collision?

A ball of clay with a mass of .1 kg hits the floor and comes to a stop. Just before it hits the floor the velocity was -5.69m/s. If the collision took .64 s, how much force is the floor exert on the ball of clay?

Answer 1

A.
Impulse is calculated through the equation,

I = mΔv

where I is impulse, m is mass and Δv is change is velocity. Substituting the known values,

I = (6 kg)(23 m/s - 6 m/s)
I = 102 kg m/s

Answer: 102 kg m/s

B.
Impulse in this item is calculated by multiplying the force by the time.


I = Force / time = (29 kg m/s²)(7 s) = 203 kg m/s

Answer: 203 kg m/s

C.
To answer this item, we have to multiply the mass and the velocity to get the impulse and divide the answer by the time to get the force.

F = m(v)/t

Substituting,

F = (0.1 kg)(-5.69 m/s)/0.64 s
F = -0.89 N

Answer: -0.89 N