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What is the constant of proportionality for the relationship shown in the table

A.1/2

B.2

C.4

D.8

What is the constant of proportionality for the relationship shown in the table A-example-1
User Iullianr
by
8.3k points

2 Answers

2 votes

Answer:

Option A is correct


(1)/(2)

Explanation:

Direct proportionality states:

if
y \propto x

then, the equation is in the form of:


y = kx ......[1] where, k is the constant of proportionality.

As per the statement:

Consider any points from the given table:

Let (x, y) = (4, 2)

Substitute these points in [1] we have;


2 = 4k

Divide both sides by 4 we have;


(1)/(2) = k

or


k=(1)/(2)

Therefore, the constant of proportionality for the relationship is,
(1)/(2)

User Yohei
by
7.9k points
4 votes

Answer:

Option A


1/2

Explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
y/x=k or
y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

so

For
x=2, y=1


k=y/x=1/2

For
x=4, y=2


k=2/4=1/2

For
x=6, y=3


k=3/6=1/2

For
x=8, y=4


k=4/8=1/2

User Ido Barash
by
7.2k points

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