Question

Which equation could solved using the graph above

Answer 1

x2 + 3x + 2 = 0

Explanation:

`x^(2) + 3x + 2 = 0`

`(x + 2) (x + 1) = 0`

`x + 2 = 0 | x +1 = 0`

`x = -2 | x = -1`

The points for the x-coordinates are -2 and -1

`(-2)^(2) + 3(-2) +2 | (-1)^(2) + 3(-1) + 2`

`4 - 3 + 2 | 1 - 3 + 2`

0 = 0

These points work.

Answer 2

Notice all the important features of the graph,

1) The graph is a parabola;
2) Roots are -2, -1
3) A point is (-3, 2)

Put all this information into an equation;

y=a(x-r)(x-s)
y=a(x+1)(x+2) <-- signs revered due to the negative sign
2=a(-3+1)(-3+2) <-- put in the values of x and y to find a
2=a(-2)(-1)
2=a(2)
2/2=a
1=a

y=(x+2)(x+1) <-- find in standard form by expanding
y= x²+x+2x+2
y=x²+3x+2

Therefore, the correct option is the second one;

Hope I helped :)