130k views
0 votes
Which equation could solved using the graph above

Which equation could solved using the graph above-example-1
Which equation could solved using the graph above-example-1
Which equation could solved using the graph above-example-2
User Trancot
by
7.5k points

2 Answers

4 votes

Answer:

x2 + 3x + 2 = 0

Explanation:


x^(2) + 3x + 2 = 0


(x + 2) (x + 1) = 0


x + 2 = 0 | x +1 = 0


x = -2 | x = -1

The points for the x-coordinates are -2 and -1


(-2)^(2) + 3(-2) +2 | (-1)^(2) + 3(-1) + 2


4 - 3 + 2 | 1 - 3 + 2

0 = 0

These points work.

Which equation could solved using the graph above-example-1
User Perazzo
by
8.7k points
2 votes
Notice all the important features of the graph,

1) The graph is a parabola;
2) Roots are -2, -1
3) A point is (-3, 2)

Put all this information into an equation;

y=a(x-r)(x-s)
y=a(x+1)(x+2) <-- signs revered due to the negative sign
2=a(-3+1)(-3+2) <-- put in the values of x and y to find a
2=a(-2)(-1)
2=a(2)
2/2=a
1=a

y=(x+2)(x+1) <-- find in standard form by expanding
y= x²+x+2x+2
y=x²+3x+2

Therefore, the correct option is the second one;

Hope I helped :)
User Jeda
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories