Question

A line passes through (3, –2) and (6, 2).

a. Write an equation for the line in point-slope form.
b. Rewrite the equation in standard form using integers.

Answer 1

A. Y= 4/3x + -6

B. 4/3x + -1y = 6

2=6* 4/3+b
2=8+b
-6=b

Answer 2

Answer with explanation:

It is given that line passes through two points (3, –2) and (6, 2).

Equation of line in point slope form with the help of formula:

`\rightarrow (y-y_(1))/(x-x_(1))=(y_(2)-y_(1))/(x_(2)-x_(1))\\\\\rightarrow (y+2)/(x-3)=(2+2)/(6-3)\\\\\rightarrow (y+2)/(x-3)=(4)/(3)-------\text{Equation for the line in point-slope form}\\\\\rightarrow 3y+6=4 x-12\\\\\rightarrow 4 x-3 y=6+12\\\\\rightarrow 4 x-3 y=18`

Standard form of line

4 x-3 y=18