From the question we have been given the rate of conversion from kilograms to pounds, which is;
![1\operatorname{kg}=2.205lb]()
Therefore, for a dog that weighs 112 pounds, the weight in kilograms shall be calculated as follows;
![\begin{gathered} 2.205lb=1\operatorname{kg} \\ (112)/(2.205)lb=x \\ 50.7936=x \\ \text{Rounded to 2 decimal places;} \\ x=50.79 \end{gathered}]()
This means the dog's weight in kilograms would be approximately 50.79 kilograms.
The prescription indicates 4.25 mg per kilogram of body weight. Hence, for a dog that weighs 50.79 kg, the dosage would be;
![\begin{gathered} 1\operatorname{kg}=4.25mg \\ 50.79\operatorname{kg}=4.25(50.79)mg \\ 50.79\operatorname{kg}=215.8575mg \\ \text{Rounded to 2 decimal places;} \\ 50.79\operatorname{kg}=215.86mg \end{gathered}]()
Next, if Denefor is available in 200ml/5mL, and the dog requires a total of 215.86 mg, then the prescription in mL would be;
This means the dog whose body weight is 112lb/50.79kg would be given 5.08ml of Denefor.
ANSWER:
![\begin{gathered} (a)50.79\operatorname{kg} \\ (b)215.86mg \\ (c)5.08ml \end{gathered}]()