Question

The U.S. Weather Bureau has a station on Mauna Loa in Hawaii that has measured carbon dioxide levels since 1959. At that time, there were 313 parts per million of carbon dioxide in the atmosphere. In 2005, the figure was 374 parts per million. Find the increase in carbon dioxide levels and the percent of increase. Round to the nearest tenth of a percent.Increase carbon dioxide levels: ______parts per millionPercent increase: ______%

Answer 1

Increase in carbon dioxide levels = 61 part per million

The percent of increase = 19.5 %

Step-by-step explanation

In 1959, there were 313 parts per million of carbon dioxide in the atmosphere.

In 2005, the figure was 374 parts per million.

The increase in carbon dioxide levels will be: (374 - 313) = 61 part per million

The percent of increase = (increase in carbon dioxide levels)/(the carbon dioxide levels in 1959) x 100

`\text{The percent of increase }=(61)/(313)*100=19.5\text{\%}`