Question

I need help with my algebra

Answer 1

27. graph the linear equation

Let's start by replacing x = 0

when x = 0, then y = -2

`\begin{gathered} 0-3y=6 \\ -3y=6 \\ -(3y)/(-3)=(6)/(-3) \\ y=-2 \end{gathered}`

so, our first point is (0 , -2)

now, our second point is when y = 0

when, y = 0 , then x = 6

`\begin{gathered} x-3\cdot0=6 \\ x-0=6 \\ x=6 \end{gathered}`

so, the second point is ( 6 , 0 )

finally, we must draw these two points on the graph and join them with a straight line.