Question

Phosphorus-32 (p-32) has a half-life of 14.2 days. if 250 g of this substance are present initially, find the amount q(t) present after t days. (round your growth constant to four decimal places.)

Answer 1

The amount of substance left out of a given amount with the given half-life and the number of days can be calculated through the equation,

q(t) = qo(0.5)^(t/h)

where q(t) is the amount of substance after t days, qo is the initial amount of substance. q(t) and q(o) should have the same units. t is the number of days and h is the half-life.