Question

Simplify evaluate the numerical bases (4^2b^3c-5)(4^-1b^-4c^8)

Answer 1

Given expression

`(4^2b^3c^(-5))(4^(-1)b^(-4)c^8)`

Rewriting each term

`4^2 = 16`

`b^3 = b^3`

`c^(-5)= (1)/(c^5)`

`4^(-1) = (1)/(4)`

`b^(-4) = (1)/(b^4)`

`c^8 = c^8`

Put them back together

`(16)(b^3)( (1)/(c^5) )( (1)/(4))( (1)/(b^4))(c^8)`

`( (16)/(4))( (b^3)/(b^4))( (c^8)/(c^5) )`

`4(b^(3-4))(c^(8-5))`

`4b^(-1)c^3`

`(4c^3)/(b)`