Question

The position of a submarine relative to the water surface was −32 1/4 feet. A downward navigational maneuver increased its depth by 15 1/2 feet. What is the position of the submarine now relative to the water surface? Enter your answer as a mixed number, in simplified form, in the bo

Answer 1

The correct answer would be -47 3/4

You would use the equation
-32 1/4 - 15 1/2 = -47 3/4
to find your answer

Answer 2

`-47(3)/(4) \text{ feet}`

Explanation:

We have been given that the position of a submarine relative to the water surface was
`-32(1)/(4) \text{ feet}`. A downward navigational maneuver increased its depth by
`15(1)/(2) \text{ feet}`.

To find the final position of submarine relative to the water surface we will add both elevation of submarine.

`\text{Final position of submarine relative to water surface}=-32(1)/(4) +(-15(1)/(2) )`

We are adding negative
`15(1)/(2) \text{ feet}` as it is downward increase in depth which will make the position of submarine more negative.

`\text{Final position of submarine relative to water surface}=(-32-15)+(-(1)/(4) -(1)/(2) )`

`\text{Final position of submarine relative to water surface}=(-47)+(-(1)/(4) -(2)/(4) )`

`\text{Final position of submarine relative to water surface}=(-47)+(-(3)/(4))`

`\text{Final position of submarine relative to water surface}=-47(3)/(4)`

Therefore, final position of the submarine relative to the water surface will be
`-47(3)/(4) \text{ feet}`.