55.9k views
3 votes
if a sequence is defined recursively by f(0 ) = 3 and f(n+1) = -f(n)+5 for n is equal to or greater than 0, then f(2) is equal to?

User Ugur Artun
by
7.9k points

2 Answers

2 votes
if f(n+1)= -f(n) +5
then f(2)=-f(1)+5
we don't know f(1) yet. Use the same rule as above:
f(1)=-f(0)+5, we do know that f(0)=3, so f(1)=-3+5=2
so f(2)=-f(1)+5=-2+5=3
User Reza Amya
by
8.5k points
0 votes

Answer:

value of f(2) is, 3

Explanation:

As per the statement::


f(0) = 3

and recursive formula is given as:


f(n+1) = -f(n)+5 .....[1]
n\geq 0

To find the value of f(2):

Substitute n = 0 in [1] we have;


f(1) = -f(0)+5


f(1) = -3+5 = 2


f(1) = 2

Now. substitute n =1 we have;


f(2) = -f(1)+5


f(2) = -2+5 = 3


f(2) = 3

Therefore, the value of f(2) is, 3

User Shany
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories