38.3k views
0 votes
you drop a ball off a cliff at 500ft. how long does it take the ball to hit the ground? h(t)= -16t^2+500

2 Answers

2 votes
h(t)=-16t^2+500
0=-16t^2+500
16t^2=500
t^2=500/16
t=±5.59 seconds
☺☺☺☺
User Drew Rush
by
8.5k points
3 votes
The height when the ball drops would be 0, so plug in 0 for h(t):
0 = -16t^2 + 500
Then you would solve for t, which in this case would equal to the time it takes to land.
-500 = -16t^2
t = 5.59, so it would take about 5.6 seconds to reach the ground.
User Tallgirltaadaa
by
7.5k points