Question

The equation of the problem (hint: what is the slope and y-intercept)-6 -24 -3 -12 0 12 3 24

Answer 1

The person above answered correctly :))

Answer 2

Given the equation of a straight line

`y=mx+c`

m is the slope and c is the intercept on the y axis

From the table in the question, the equation of the line can be obtained using two points form the equation of a straight line

`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

Pick two points on the table and substitute for the x values and y values

`(-6,-24)\text{ and (3, -12)}`
`\begin{gathered} x_1=-6,y_1=-24 \\ x_2=-3,y_2=-12 \end{gathered}`
`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(-12-(-24))/(-3-(-6))=(-12+24)/(-3+6)=(12)/(3)=4 \end{gathered}`
`\begin{gathered} y=mx+c \\ -24=4(-6)+c \\ -24=-24+c \\ c=-24+24=0 \end{gathered}`

Hence, the equation of the table is y = 4x