Question

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The coordinates of   square ABCD

 are  A(0, 0)  ,  B(a, 0)  , C(, a), and  D(0, ).

The slope of  AC ¯¯¯¯¯  , when simplified, is equal to .

The slope of  BD ¯¯¯¯¯ , when simplified, is equal to  −1  .

The product of the slopes is equal to .

Therefore,  AC ¯¯¯¯¯  is perpendicular to  BD ¯¯¯¯¯

. Complete the coordinate proof of the theorem.

Answer 1

1: a

2: a

3: 1

4: -1

Step-by-step explanation:

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Answer 2

The slope of AC, when simplified, is equal to 1. The product of the slopes is equal to -1.