Question

Find the distance between (3, -7) and (-2, 13)

Answer 1

20.62units

Step-by-step explanation:

Given the coordinate points (3, -7) and (-2, 13)

The distance between two coordinate point is expressed as;

`D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`

Substituting the coordinate points

`\begin{gathered} D=\sqrt[]{(-2_{}-3)^2+(13_{}+7)^2} \\ D=\sqrt[]{(-5_{})^2+(20)^2} \\ D=\sqrt[]{25+400^{}} \\ D=\sqrt[]{425^{}} \\ D\text{ = }20.62\text{units} \end{gathered}`

Hence the distance between the coordinate points is 20.62units