Question

To a stationary observer, a bus moves north with a speed of 10 m/s. A man inside walks toward the back of the bus with a speed of 0.4 m/s relative to the bus. What is the velocity of the man according to a stationary observer?

Answer 1

9.6m/s - apex .........................

Answer 2

v = 9.6 m/s

Step-by-step explanation:

Here we know that velocity is bus is

`v = 10 m/s`

also the person inside the bus is moving in opposite direction with repect to bus at speed of 0.4 m/s

now we know that

`\vec v_(12) = \vec v_1 - \vec v_2`

now we know that

`\vec v_(12) = -0.4 m/s`

`v_1 = ?`

`v_2 = 10 m/s`

now we have

`-0.4 = v_1 - 10`

`v_1 = 9.6 m/s`

so velocity of man is 9.6 m/s in direction of bus with respect to stationary observer