Question

Write a balanced chemical equation for the standard formation reaction of solid potassium dichromate k2cr2o7

Answer 1

The balanced chemical equation for the standard formation of solid potassium dichromate (K₂Cr₂O₇) is 4 K(s) + 2 Cr(s) + 7 O₂(g) → 2 K₂Cr₂O₇(s).

Step-by-step explanation:

The balanced chemical equation for the standard formation reaction of solid potassium dichromate (K₂Cr₂O₇) involves the combination of the elements in their standard states to form the compound. The standard states for potassium, chromium, and oxygen are solid potassium (K), solid chromium (Cr), and diatomic oxygen gas (O₂), respectively. Thus, the balanced equation for the standard formation of potassium dichromate is:

4 K(s) + 2 Cr(s) + 7 O₂(g) → 2 K₂Cr₂O₇(s)

In this reaction, four potassium atoms react with two chromium atoms and seven molecules of diatomic oxygen to form two formula units of solid potassium dichromate.

Answer 2

7/2 O2(g)+2K(s)+2Cr(s)=K2Cr2O7(s)

Explanation:

1.) Identify the elements: potassium dichromate contains oxygen, potassium, and chromium.

2.) Identify the standard states of each element: the standard state of oxygen is O2(g), the standard state of potassium is K(s), and the standard state of chromium is Cr(s).

3.)Write and balance the formation:

a. written out: O2(g)+ K(s)+Cr(s)=K2Cr2O7

b. Balanced: 7O2(g)+4K(s)+4Cr=2K2Cr2O7

4.) Make sure there is only 1 Mol of the compound, you have to divide everything by 2, this gives you the following:

7/2 O2(g)+ 2K(s)+2Cr(s)=K2Cr2O7

**

The 7/2 on the oxygen make it so you can balance without making more than 1 mol of the compound. Hope this helps!