Question

If a particle undergoes shm with amplitude 0.10 m , what is the total distance it travels in one period?

Answer 1

The total distance traveled by a particle in one period of simple harmonic motion (SHM) is equal to 4 times the amplitude of the oscillation.

Step-by-step explanation:

In simple harmonic motion (SHM), the particle oscillates back and forth around its equilibrium position. The total distance traveled by the particle in one period of SHM is equal to 4 times the amplitude of the oscillation.

Therefore, if the amplitude of the particle's SHM is 0.10 m, then the total distance it travels in one period is 4 x 0.10 m = 0.40 m.

Answer 2

If the amplitude is equal to 0.25m, then the distance travelled above and below the equilibrium is also equals to 0.25m. it means if it starts above the equilibrium, one period will be completed when it returns back to its original position so, it travels 0.25 below, 0.25m back, 0.25m down and o.25 m when it comes back to its original position, so the total distance we get is by adding 0.25m 4 times that is 1m.