Question

How much heat is absorbed by a 125 g sample of water when it is heated from 25.20 ºc to 32.80 ºc? the specific heat of water is 4.184 j/g ºc?

Answer 1

We can use the equation of
E = mc△T
To calculate the total heat absorbed.
E is the total heat absorbed (energy used)
m is mass.
c is specific heat capacity and
△T is the temperature change.
E = 125 x 4.184 x (32.8 - 25.2)
E = 3974.8 J
Therofre the total heat absorbed is 3974.8 joules.