The average rate of change of the function f(x)=4x^3 + 4 over the interval [66,88] is

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asked Feb 7, 2018 219k views

1 Answer

Thomas Rushton · Answer 1 · 2018-02-11T10:04:50+0000

Average rate of change =[f (x₂)-f (x₁)]/(x₂-x₁)

Interval [66,88] which is x₁=66, x₂=88

f (x)=4x³+4
f (x₁)=f (66)=4 (66)³+4=1149988
f (x₂)=f (88)=4 (88)³+4=2725892

Average rate of change =2725892-1149988/88-66
=1575904/22
=71632

The average rate of change of the function f(x)=4x^3 + 4 over the interval [66,88] is

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The average rate of change of the function ​f(x)=4x^3 + 4 over the interval ​[66​,88​] is

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The average rate of change of the function f(x)=4x^3 + 4 over the interval [66,88] is