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A) 104 units^2 B) 2184 units^2 C) 248 units^2 D) 250 units^2

A) 104 units^2 B) 2184 units^2 C) 248 units^2 D) 250 units^2-example-1
User Robert Townley
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1 Answer

25 votes
25 votes

First find the perimeter of the rectangle

P = 2(l+w) where l is the length and w is the width

P = 2( 5x-1+x)

Combine like terms

P = 2( 6x-1)

P = 12x -2

Find the perimeter of the triangle

P = s1 + s2 +s3 where s is the side length

P = 5x+12+ 6x+7

Combine like terms

P = 11x+19

We are told the perimeters are equal

12x-2 = 11x+19

Subtract 11x from each side

12x-2 -11x = 11x+19-11x

x-2 = 19

Add 2 to each side

x-2+2 = 19+2

x = 21

The side lengths of the rectangle are

x=21 and 5x-1 = 5*21 -1 = 105-1 = 104

We can find the area

A = l*w where l is the length and w is the width

A = 21 * 104

A = 2184 units^2

Answer:

B 2184 units^2

User Marcelo Camargo
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3.0k points