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From triangle midsegment theorem we know, that a midsegment connecting two sides of a triangle is parallel to the third side and is half as long, so:

1.

Midsegment length = 6x+4
Third side length = 4x+56

and


4x+56=2\cdot(6x+4)\\\\4x+56=12x+8\quad|-4x\\\\4x+56-4x=12x+8-4x\\\\56=8x+8\quad|-8\\\\56-8=8x+8-8\\\\48=8x\quad|:8\\\\\boxed{x=6}

so midsegment length:


L=6x+4=6\cdot(6)+4=36+4=\boxed{40}

Answer C.

2.

The tree is a midsegment so it is half as high as a building:


\text{Tree } =120:2=\boxed{60\,\text{ft}}

Answer A.
User Zeehad
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