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Find the number of real number solutions for the equation. x2 + 0x − 1 = 0

User Fahrulazmi
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2 Answers

3 votes

Final answer:

Using the quadratic formula for the equation x2 + 0x - 1 = 0, we find two real number solutions, which are x = 1 and x = -1.

Step-by-step explanation:

To find the number of real number solutions for the equation x2 + 0x - 1 = 0, we can use the quadratic formula, which is applicable for equations of the form ax2 + bx + c = 0. The quadratic formula is given by:



x = (-b ± √(b2 - 4ac)) / (2a)



For our equation, a = 1, b = 0, and c = -1. Plugging these into the formula, we get:



x = (0 ± √((0)2 - 4(1)(-1))) / (2(1))
= ± √(4) / 2
= ± 2 / 2



Thus, we have two possible solutions for x: x = 1 and x = -1. Since both of these values are real numbers, the equation has two real number solutions.

User Gearoid Murphy
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0 votes

Answer:

x=1 or x=−1 its either one of the other.

Step-by-step explanation:

User Sfaust
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