Question

The equation of line m is 3x−5y=−4.

What is the slope of a line that is perpendicular to line m?

Answer 1

The comments are locked so

Are u sure that's the answer? Because this is on my unit test: 4.10 and i can't really afford to get a trade power than a 'B'

Answer 2

the equation of a perpendicular line to another, is the negative reciprocal of the other, or each other, so hmm let's see what's the slope of 3x -5y = -4 then


`\bf 3x-5y=-4\implies 3x+4=5y\implies \cfrac{3x+4}{5}=y\implies \stackrel{slope}{\cfrac{3}{5}}x+\stackrel{}{\cfrac{4}{5}}=y`

so, what is the slope of a line perpendicular to that one then?


`\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{3}{5}\\\\ slope=\cfrac{3}{{{ 5}}}\qquad negative\implies -\cfrac{3}{{{5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{3}`