Question

What is the equation of the line on the graph ?

Answer 1

hello

the equation of a straight line is given as

`\begin{gathered} y=mx+b \\ b=\text{intercept} \\ m=\text{slope} \end{gathered}`
`\text{slope}=(y_2-y_1)/(x_2-x_1)`

from the graph given the values of the co-ordinates are given as

`\begin{gathered} y_2=280 \\ x_2=20 \\ y_1=120 \\ x_1=0 \end{gathered}`

now let's substitute the values into the equation and solve

`\begin{gathered} \text{slope}=(y_2-y_1)/(x_2-x_1) \\ \text{slope}=(280-120)/(20-0) \\ \text{slope(m)}=(160)/(20) \\ \text{slope(m)}=8 \end{gathered}`

from the calculations above, the slope of the line is equal to 8 and also the y-intercept is equal to 120

the equation of the line =

`\begin{gathered} y=mx+b \\ m=8 \\ b=120 \\ y=8x+120 \end{gathered}`

the equation of the line is y = 8x + 120 and this correspo