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What is the average rate of change of the function f(x)=480(0.3)^x from x = 1 to x = 5?

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2 Answers

5 votes
average = [f(15) - f(1)] / (5 - 1)
average = [480(0.3)^5 - 480(0.3)^1] / 4
average = [480(0.3)^5 - 480(0.3)^1] / 4
average = (1.1664 - 144)/4
average = -35.7084
User Teena Thomas
by
8.5k points
5 votes

Answer: The average rate of change of function f(x) is -35.7084.

Step-by-step explanation:

The given function is,


f(x)=480(0.3)^x

Where to find the rate of change of function from x=1 to x=5.

Put x=1


f(1)=480(0.3)^(1)=144

put x=5.


f(5)=480(0.3)^(5)=1.1664

Rate of change is,


Slope=\frac{\text{Change is f(x)}}{\text{Change is x}}


m=(f(5)-f(1))/(5-1)


m=(1.1664-144)/(4)


m=(-142.8336)/(4)


m=-35.7084

Therefore the rate of change is -35.7084. It means the function f(x) decreases by 35.7084 units as x increases by 1 unit.

User Wogan
by
7.7k points

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