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Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in celina’s measurement?
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Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in celina’s measurement?

User DhrubaJyoti
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The answer would be 0.45 feet because you have to take the 6 and subtract 5.55 feet from it. Your equation would be x+5.55=6.
User Thang Nguyen
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