Question

A baseball with a mass of 0.145 kilograms collides with a bat at a velocity of 44 meters/second. The ball bounces off the bat with a speed of 49 meters/second in the opposite direction. What is the impulse?A baseball with a mass of 0.145 kilograms collides with a bat at a velocity of 44 meters/second. The ball bounces off the bat with a speed of 49 meters/second in the opposite direction. What is the impulse?

Answer 1

Answer: 13.485 Ns impulse in the opposite direction

Step-by-step explanation:

Answer 2

Momentum= FΔt=mΔv=Δp

Assuming that the initial direction of the ball is negative;

(0.145)(49-(-44)) <-- Δv= final velocity-initial
(0.145)(49+44)
= 13.485 Ns impulse in the opposite direction

Hope I helped :)