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naturally occurring rubidium consists of about 73.2% rubidium-85 (atomic mass 84.9 u) and 27.8% rubidium-87 (atomic mass 86.9 u). calculate the average atomic mass of rubidium rounding your answer to 0.1 u

User Udo Held
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The answer based on the question would be 86.3.  How that answer was derived is attached below.
naturally occurring rubidium consists of about 73.2% rubidium-85 (atomic mass 84.9 u-example-1
User Jack Nutkins
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You can find the average by adding rubidium-85's and -87's weights then dividing the sum by two. I'm fairly certain it's 85.9 u but I would check my work
User Davlog
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