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In a rectangular coordinate plane what is the distance between points (-3,0) and (3,8)

User Anhldbk
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1 Answer

7 votes

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:



\mathsf{d=√((x_2-x_1)^2+(y_2-y_1)^2)}


"d" represents the distance and coordinates are expressed as follows: (x, y)


Let's go to the calculations.



\mathsf{d=√((x_2-x_1)^2+(y_2-y_1)^2)}\\\\ \mathsf{d=√((3-(-3))^2+(8-0)^2)}\\\\ \mathsf{d=√((3+3)^2+(8)^2)}\\\\ \mathsf{d=√((6)^2+64)}\\\\ \mathsf{d=√(36+64)}\\\\ \mathsf{d=√(100)}\\\\ \underline{\mathsf{d=10}}


The answer is 10 uc.

User Flezcano
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