Final answer:
From 2.86 mol of N₂ and excess H₂, 97.38 grams of NH₃ can be produced, based on the balanced chemical equation and molar mass of NH₃.
Step-by-step explanation:
The student's question is about calculating the mass of NH₃ that can be produced from a given amount of N₂ in a chemical reaction with excess H₂.
The balanced chemical equation for the reaction is:
N₂(g) + 3H₂(g) → 2NH₃(g)
Here, 1 mol of N₂ produces 2 mol of NH₃.
Since the student has 2.86 mol of N₂, this would theoretically yield 2 * 2.86 = 5.72 mol of NH₃.
To find the mass of NH₃ produced, we use its molar mass (17.03 g/mol).
Multiplying the number of moles by the molar mass gives us the mass of NH₃:
5.72 mol * 17.03 g/mol = 97.38 grams of NH₃.
Thus, the student can expect to produce 97.38 grams of NH₃ from 2.86 mol of N₂ with excess H₂.