211k views
2 votes
A group of 463 first-year college students were asked, “About how many hours do you study during a typical week?” The mean response is 15.3 hours. Assume that the study time is normally distributed with a sample standard deviation of 8.5 hours. Construct a 99% confidence level interval for the mean study time of all first-year students.

User Audrea
by
6.7k points

1 Answer

5 votes
For a known standard deviation a confidence level of 99% we may consider Z=2.576.
So, the confidence interval would be calculated by:

mean-Z(standard~deviation)/( √(number~of~students~in~the~group) ) ,
mean+Z(standard~deviation)/(√(number~of~students~in~the~group) )

15.3-2.576 (8.5)/( √(463) ) ,
15.3+2.576 (8.5)/( √(463) )

15.3-1.018 ,
15.3+1.018

14.282 ,
16.318
Considering the given data, with a 99% cofidence, it can be said that the true mean of hours of study in a typical week for first-year college students is between 14.282 and 16.318.
User Hugs
by
6.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.