Question

How many moles of ions will be present in 716 ml of 0.450 m solution of sodium phosphate(aq)?

Answer 1

Answer: Number of moles of ions in 0.716 L of 0.450 M solution is 1.2888 moles.

Solution:

`Na_3PO_4(aq)\rightarrow 3Na^+(aq)+PO_4^(3-)(aq)`

Volume of the solution 716 mL

Molarity of the solution : 0.450 M

`Molarity=\frac{\text{Number of moles}}{\text{Volume in Liters}}`

`0.450 mol/L=\frac{\text{Number of moles of }Na_3PO_4}{0.716 L}`

`\text{Number of moles of }Na_3PO_4=0.450mol/L* 0.716=0.3222 moles`

According to reaction one mol
`Na_3PO_4` is giving 4 moles of ions.

Number of moles of ions in 0.716 L of 0.450 M solution is =
`4* 0.3222=1.2888 moles`

Hence,number of moles of ions in 0.716 L of 0.450 M solution is 1.2888 moles.