Question

A car accelerates uniformly from rest to a speed of 70.3 km/h (19.5 m/s) in 11 s. Find the distance the car travels during this time.

Answer 1

Given data

*The given initial speed of the car is u = 0 m/s

*The given final speed of the car is v = 19.5 m/s

*The given time is t = 11 s

The formula for the acceleration of the car is given as

`a=(v-u)/(t)`

Substitute the known values in the above expression as

`\begin{gathered} a=(19.5-0)/(11) \\ =1.77m/s^2 \end{gathered}`

The formula for the distance by the car travels is given by the equation of motion as

`d=ut+(1)/(2)at^2`

Substitute the known values in the above expression as

`\begin{gathered} d=(0)(11)+(1)/(2)(1.77)(11)^2 \\ =107.08\text{ m} \end{gathered}`